19999: Near Repdigit 199..99

First few terms (base 10): \[[19^*_{10}]_n=\{1,19,199,1999,19999,\ldots\}\]

General Formula:\[[19^*_{10}]_n=2\cdot10^{n}-1\]

Equivalent Patterns: \[[59^*7_{10}]_n=3\cdot[19^*_{10}]_{n+1}\] \[[39^*8_{10}]_n=2\cdot[19^*_{10}]_{n+1}\] \[[79^*6_{10}]_n=4\cdot[19^*_{10}]_{n+1}\] \[[9^*5_{10}]_n=5\cdot[19^*_{10}]_n\]

See Also: Factorization of 199..99 on stdkmd.net

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